0 个投票

i am trying to compare the two different array in loop to get the number of times the value are coming in X1 which are in X2 but i m getting the wromg answer
clc
clear all
x1=[1,2,3,2,0,3,4,3,5,4,5,6,8];
x2=[3,0];
for m=1:length(x2)
for i=1:length(x1)
s(m)=(nnz((x1(i))==x2(m)));
end
end
s

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 采纳的回答

Stephan
Stephan 2019-8-12

0 个投票

x1=[1,2,3,2,0,3,4,3,5,4,5,6,8];
x2=[3,0];
res = zeros(1,numel(x2));
for k = 1:numel(x2)
res(k) = sum(ismember(x1,x2(k)));
end

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