Combination of sub-matrices generated within a for loop

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Rengin
Rengin 2019-8-13
评论： Bruno Luong 2019-8-13
clear;
clc;
close all;
n=[3 1 2];
rad=[0.04 0.02 0.01];
h=[10 12 15];
for kk=1:length(n)
matrix=zeros(n(kk),n(kk));
for ii=1:n(kk)
for jj=1:n(kk)
val=rad(kk)*h(kk);
matrix(ii,jj)=val;
end
end
end
% Dear users, if you put a debug at the very last "end" (row 17), you can
% see that I aim to generate 3 sub-matrices having the size of 3x3, 1x1 and
% 2x2 (see n=[3 1 2]). I want to combine each sub-matrix one each other diagonally.
% I want to get the matrix as a result below:
matrix=[0.4 0.4 0.4 0 0 0;0.4 0.4 0.4 0 0 0;0.4 0.4 0.4 0 0 0;0 0 0 0.24 0 0;0 0 0 0 0.15 0.15;0 0 0 0 0.15 0.15];
%Is there any simple way to do it?
%Thanks in advance!
  3 个评论
显示 1更早的评论
madhan ravi
madhan ravi 2019-8-13
Using the previous solution of your question gives the same result, please describe the situation where that condition contradicts your needs.
Bruno Luong
Bruno Luong 2019-8-13
"The calculation of Val is different."
You might try to learn deeper how computer programming actually works, if you get stuck everytime the values change then you miss the whole purpose of programming.

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采纳的回答

infinity
infinity 2019-8-13
Hello,
There are various solutions for this question, one of the closet one to your current code could be
clear;
clc;
close all;
n=[3 1 2];
rad=[0.04 0.02 0.01];
h=[10 12 15];
matrix = zeros(sum(n));
for kk=1:length(n)
% matrix=zeros(n(kk),n(kk));
for ii=1:n(kk)
for jj=1:n(kk)
val=rad(kk)*h(kk);
matrix(ii+sum(n(1:kk-1)),jj+sum(n(1:kk-1)))=val;
end
end
end

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