Translation of a 3D plane

2 次查看(过去 30 天)
Phanikumar Bhamidipati
I have a set of 3D points out of which I have fitted a plane using Principal Component Analysis. Now, I want to generate/create a plane parallel to this one at a particular distance or passing through a point and find how these individual points project on that new plane.
Any help or input is appreciated.
The following code is an example.
randn('state',0);
X = mvnrnd([0 0 0], [1 .2 .7; .2 1 0; .7 0 1],50);
plot3(X(:,1),X(:,2),X(:,3),'bo');
grid on;
maxlim = max(abs(X(:)))*1.1;
axis([-maxlim maxlim -maxlim maxlim -maxlim maxlim]);
axis square
view(-23.5,5);
[coeff,score,roots] = princomp(X);
basis = coeff(:,1:2)
normal = coeff(:,3)
n,p] = size(X);
meanX = mean(X,1);
Xfit = repmat(meanX,n,1) + score(:,1:2)*coeff(:,1:2)';
residuals = X - Xfit;
error = abs((X - repmat(meanX,n,1))*normal);
sse = sum(error.^2)
[xgrid,ygrid] = meshgrid(linspace(min(X(:,1)),max(X(:,1)),5), ...
linspace(min(X(:,2)),max(X(:,2)),5));
zgrid = (1/normal(3)) .* (meanX*normal - (xgrid.*normal(1) + ygrid.*normal(2)));
h = mesh(xgrid,ygrid,zgrid,'EdgeColor',[0 0 0],'FaceAlpha',0);
hold on
above = (X-repmat(meanX,n,1))*normal > 0;
below = ~above;
nabove = sum(above);
X1 = [X(above,1) Xfit(above,1) nan*ones(nabove,1)];
X2 = [X(above,2) Xfit(above,2) nan*ones(nabove,1)];
X3 = [X(above,3) Xfit(above,3) nan*ones(nabove,1)];
plot3(X1',X2',X3','-', X(above,1),X(above,2),X(above,3),'o', 'Color',[0 .7 0]);
nbelow = sum(below);
X1 = [X(below,1) Xfit(below,1) nan*ones(nbelow,1)];
X2 = [X(below,2) Xfit(below,2) nan*ones(nbelow,1)];
X3 = [X(below,3) Xfit(below,3) nan*ones(nbelow,1)];
plot3(X1',X2',X3','-', X(below,1),X(below,2),X(below,3),'o', 'Color',[1 0 0]);
hold off
maxlim = max(abs(X(:)))*1.1;
axis([-maxlim maxlim -maxlim maxlim -maxlim maxlim]);
axis square
view(-23.5,5);
  4 个评论
Andrew Newell
Andrew Newell 2011-4-5
Is this code not doing what you want?
Phanikumar Bhamidipati
This one gives a best fit plane minimizing the MSE. Once that plane is found, I would like to move the plane by a certain distance. that was the original question.

请先登录,再进行评论。

回答(1 个)

Tim Zaman
Tim Zaman 2011-4-6
Try RANSAC, i've got some on that here: http://www.timzaman.nl/?p=190

类别

Help CenterFile Exchange 中查找有关 Dimensionality Reduction and Feature Extraction 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by