retime only for specific gaps on time

4 次查看（过去 30 天）
Rub Ron
Rub Ron 2019-8-14
编辑： Akira Agata 2019-8-15
I have a timetable z with more than 10 000 rows, this timetable should have a resolution of 15 minutes, but there are gaps of for example 30,45 minutes, 1, 5, 8 hours, or even days. So I would like to fill the missing data using retime but only for the gaps lower or equal to a specific gap (for example 1 hour). How can I do that? I have search for ways of doing that, but have found no hint. I am using this line, but it fills all the gaps.
retime(z,'regular','linear','TimeStep',minutes(15))
Any help would be very much appreciatted.
  1 个评论
dpb
dpb 2019-8-14
No builtin method I know of...first thought comes to my mind would be to build a corollary variable of the time gap values exceeding your threshold and then removing the interpolated rows between those time intervals after retime does its thing.

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Akira Agata
Akira Agata 2019-8-15
编辑：Akira Agata 2019-8-15
How about the following solution?
% Sample timetable with 2 gaps (e.g >1 hour)
Time = datetime('now') + minutes(cumsum(45*rand(100,1)));
Time(30:end) = Time(30:end) + hours(1); % Gap1
Time(60:end) = Time(60:end) + hours(1); % Gap2
Data = rand(100,1);
TT = timetable(Time,Data);
% Find gaps and create group vector
idx = diff(TT.Time) > hours(1);
idx = [true; idx];
group = cumsum(idx);
% Apply retime function for each group and concatenate the result
TT2 = [];
for kk = 1:max(group)
idx = group == kk;
TT2 = [TT2; retime(TT(idx,:),'regular','linear','TimeStep',minutes(15))];
end

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Timetables 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by