Info

此问题已关闭。 请重新打开它进行编辑或回答。

How do you rearragne a matrix?

1 次查看（过去 30 天）
KieranSQ
KieranSQ 2019-8-14
关闭： MATLAB Answer Bot 2021-8-20
I am trying to vectorise a matrix of by using the data:
AN=[0,0.500000000000000,0,0.500000000000000,0.500000000000000,0,0,0.500000000000000,0,0.500000000000000,1,0.500000000000000,0,0.500000000000000,0.500000000000000,0.500000000000000,1,0.500000000000000,0.500000000000000,1,1,0.500000000000000,1,1;0,0,0.500000000000000,0,0.500000000000000,0.500000000000000,0.500000000000000,0.500000000000000,1,0.500000000000000,0.500000000000000,1,1,0.500000000000000,1,0,0,0.500000000000000,1,0.500000000000000,1,0.500000000000000,0,0.500000000000000]
Then I want to produce a 2x16 matrix where by
TEMP = [AN(1,3:3:end)-AN(1,1:3:end),AN(2,3:3:end)-AN(2,1:3:end);AN(1,2:3:end)-AN(1,1:3:end),AN(2,2:3:end)-AN(2,1:3:end)]
gives me a 2x16 matrix with the first two rows (1:2,:) being matrix 1 and the next set (3:4,:) being matrix 2 and so on. I have tried reshape but have failed to get this working. I want something like this, where 1) is the matrix number:
0 0.5
0.5 0
-0.5 0.5
0 0.5
. .
. .
. .
0.5 0
0.5 -0.5
Any advice would be appreciated. I am trying to avoid for loops for speed as my matricies become extremely large.

请先登录，再回答此问题。

回答（1 个）

Athul Prakash
Athul Prakash 2019-8-19
After the 2 lines of code above, use
res = reshape(TEMP, [16 2])
See the documentation here:
https://www.mathworks.com/help/matlab/ref/reshape.html
(The code shown above produces the exact same output you mentioned in your question.)

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by