converting points on cell array

2019 8 17
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更新时间：2019 8 19
2 次查看（30 天）

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Hi I want to display points as cell. but it gives error at t
for i=0:n-1
t=(find({Y2}=={(X(i+1))}));
if (~isempty(t))
temp=[ones(1,length(t)).*i; t-1];
.
.
error at
t=(find({Y2}=={(X(i+1))}));
Undefined operator '==' for input arguments of type 'cell'
Can anyone tell me whats wrong here

6 个评论
显示 4更早的评论 隐藏 4更早的评论

madhan ravi
madhan ravi 2019-8-17
{Y2} why? Instead of Y2 ??, upload the missing datas.
Walter Roberson
Walter Roberson 2019-8-17
What is your expectation for how {Y2}=={(X(i+1))} would work? Is there a reason you are not using Y2==(X(i+1)) ?
sadiqa ilyas
sadiqa ilyas 2019-8-17
Y2={[]};X={[]}
for x=0:n-1
Y2={[Y2 powermod(x,2,n)]};
X={[X mod(x^3+a*x+b,n)]};
end
E=[];
for i=0:n-1
t=(find({Y2})==({(X(i+1))}));
if (~isempty(t))
temp=[ones(1,length(t)).*i; t-1];
E=[E temp];
end
end
I want points in cell form
sadiqa ilyas
sadiqa ilyas 2019-8-17
i want points appear in cell form.
Are Mjaavatten
Are Mjaavatten 2019-8-19
What do you mean by points? And why use cell arrays?
I have modified your code so that it runs, but this may not be what you want. Could you explain in more detail what you are attempting to do?
n = 4;a = 1; b = 3;
Y2 = cell(n,1);X=cell(n,1);
for x=1:n
Y2{x} = powermod(x,2,n);
X{x} = mod(x^3+a*x+b,n);
end
E=[];
for i=0:n-1
t=find(cell2mat(Y2)==X{i+1});
if (~isempty(t))
temp=[ones(length(t),1)*i; t-1];
E=[E temp];
end
end
sadiqa ilyas
sadiqa ilyas 2019-8-19
I am using cell because i am trying to do mapping using elliptic curves. The code you have written gives me points like
0 1 2
0 1 2
0 0 0
2 2 2

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