Does the use of latency in statflow state work as expected?
6 次查看(过去 30 天)
显示 更早的评论
Hi, I have a problem with stateflow, which is if I use a delay function in the state to execute two sentences, does that delay function work?
Because the compilation prompted me to delete, so I hope you help me,thanks!
This temporal logic expression has no side-effect. It either needs to be used in an expression, or removed if deemed unnecessary. State 'init' in Chart 'BLDDPM_cpu1_CCP_V1_0_20190818/extraControl/Protect_Logic': after(1,sec);
0 个评论
采纳的回答
Jonas
2019-8-19
编辑:Jonas
2019-8-19
Your state expression will not work indeed. You will need to create an additional state where ProtectStartBit = uint16(1); which has a state transition leading towards it with the condition after(1,sec);.
5 个评论
Jonas
2019-8-19
Stateflow does not work that way, all expressions within one state are executed each sample time when active. You need to separate the expressions in separate states.
更多回答(0 个)
另请参阅
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!