Replace one NAN with zero in a row vector without a loop
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I have a row vector that its size is changing in each run. Some of its elements might be NAN and I want to replace those with zero.
How can I do that without need to have a loop? isnan(A) finds nan values but I need to replace and I want to avoid loop.
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Raj
2019-8-19
A(isnan(A)) = 0; % replaces NAN elements of A matrix by Zero.
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