Integers can only be combined with integers of the same class, or scalar doubles.

4 次查看（过去 30 天）
Sajina Rose
Sajina Rose 2019-8-21
评论： Guillaume 2019-8-21
red=I(:,:,1);
green=I(:,:,2);
blue=I(:,:,3);
R=(0.7*GRmean+(1-0.7)*LRmean);
G=(0.7*GGmean+(1-0.7)*LGmean);
B=(0.7*GBmean+(1-0.7)*LBmean);
r=red./R; %ERROR
g=green./G;
b=blue./B;
  3 个评论
显示 1更早的评论
Sajina Rose
Sajina Rose 2019-8-21
Yeah.....I defined formula for that in my code.......It's nothing but just global and local mean of RGB....

请先登录，再进行评论。

请先登录，再回答此问题。

回答（1 个）

John D'Errico
John D'Errico 2019-8-21
READ THE ERROR MESSAGE!
R = uint8(1:5);
>> R./double(R)
Error using ./
Integers can only be combined with integers of the same class, or scalar doubles.
Is double( R ) a scalar double? In fact, it is not. It is a vector of doubles.
So MATLAB will not allow you to perform that operation. The information was completely contained in the error message, if you think about what it says and what you just did.
Can you fix it? Well, yes, that is trivial. In the line:
r=red./R;
Change it to read
r=double(red)./R;
red is a vector of INTEGERS. R is a vector of doubles. So to do that operation, you need to convert the vector red into a vector of doubles.
  1 个评论
Guillaume
Guillaume 2019-8-21
Another option would be to convert the original image to double with im2double:
I = im2double(I);
%rest of the code as it was
matlab expects images of type double to have intensities in the range 0-1, so im2double may be better than straight double conversion.
But yes, the error message explained what the problem is.

请先登录，再进行评论。

类别

在 Help Center 和 File Exchange 中查找有关 Convert Image Type 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by