running matrix in a loop to produce another matrix
1 次查看(过去 30 天)
显示 更早的评论
Hi everyone, I have z
z = [1 1 0 0;
1 0 1 0;
1 0 0 1;
0 1 1 0;
0 1 0 1;
0 0 1 1;]
each of z's row are states that I want my code to go through one by one (from 1 1 0 0 to 0 0 1 1) , and after each state is run, it produces w. after running all the 6 states from z,
w = [a;
a;
a;
a;
a;
a;];
Is there a code where I can run each state of z in a loop, and produces w?
采纳的回答
Ted Shultz
2019-8-22
This code will loop over each row of Z and put the results into w. I'm not sure what you want to do with each row.
z = [1 1 0 0;
1 0 1 0;
1 0 0 1;
0 1 1 0;
0 1 0 1;
0 0 1 1;]
numRows = size(z,1); % counts the number of rows
w = nan(numRows,1); % preallocate w;
for ii = 1:numRows
thisRow = z(ii,:);
% do something here to get a?
a=sum(thisRow);
w(ii) = a;
end
更多回答(0 个)
另请参阅
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!