running matrix in a loop to produce another matrix

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JL 2019-8-22

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https://ww2.mathworks.cn/matlabcentral/answers/477236-running-matrix-in-a-loop-to-produce-another-matrix

评论： JL 2019-8-22

采纳的回答： Ted Shultz

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Hi everyone, I have z

z = [1	1	0	0;
0	1	0;
0	0	1;
1	1	0;
1	0	1;
0	1	1;]

each of z's row are states that I want my code to go through one by one (from 1 1 0 0 to 0 0 1 1) , and after each state is run, it produces w. after running all the 6 states from z,

w = [a;
    a;
    a;
    a;
    a;
    a;];

Is there a code where I can run each state of z in a loop, and produces w?

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Ted Shultz 2019-8-22

what is "a"?

JL 2019-8-22

"a" is calculated number. Meaning, for each time it loop, "a" is generated until the loop finishes.

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采纳的回答

Ted Shultz 2019-8-22

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https://ww2.mathworks.cn/matlabcentral/answers/477236-running-matrix-in-a-loop-to-produce-another-matrix#answer_388681

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This code will loop over each row of Z and put the results into w. I'm not sure what you want to do with each row.

z = [1  1   0   0;
1   0   1   0;
1   0   0   1;
0   1   1   0;
0   1   0   1;
0   0   1   1;]
 
numRows = size(z,1); % counts the number of rows
 
w = nan(numRows,1); % preallocate w;
 
for ii = 1:numRows
    thisRow = z(ii,:);
    
    % do something here to get a?
    a=sum(thisRow);
    
    w(ii) = a;
end