Problem with indefinite integral

2019 8 23
1 个回答
更新时间：2019 8 23
14 次查看（30 天）

0 个投票

why does the indefinite integral shows incorrect result??
how to get the constant term lost back??

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回答（1 个）

Walter Roberson
Walter Roberson 2019-8-23

0 个投票

https://www.mathworks.com/help/symbolic/int.html#btydjvs-2
TIPS
  • Results returned by int do not include integration constants.
If you need a constant of integration, then add one yourself.
"why does the indefinite integral shows incorrect result??"
What leads you to say that the results are wrong?
>> int(2*sin(t)+3*cos(t))
ans =
6*cos(t/2)*sin(t/2) - 4*cos(t/2)^2
>> diff(ans,t)
ans =
3*cos(t/2)^2 - 3*sin(t/2)^2 + 4*cos(t/2)*sin(t/2)
>> simplify(ans)
ans =
3*cos(t) + 2*sin(t)
Looks consistent to me.

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