how to find the equality of 2 numbers?

Question

Sivakumaran Chandrasekaran 2012-9-10

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采纳的回答： Andrei Bobrov

a e

1 1

1 2

3 2

The above is my input table. Check 'a' for the value '1'. The corresponding 'e' value differs. So, we should not consider it. Check 'a' the value of '3'. The corresponding 'e' values are same. How to develop code for this?

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Image Analyst 2012-9-10

Then see my answer. Also, what does "class(a)" show when you issue that command? If you want to make absolutely sure a and e are integers, wrap them in an int32() when you create them.

Walter Roberson 2012-9-10

Please retag this question; see http://www.mathworks.co.uk/matlabcentral/answers/43073-a-guide-to-tags

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Answer 1

Andrei Bobrov 2012-9-10

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AE = [a e]; %The initial array
out = AE(abs(diff(AE,1,2)) < eps(100),:);

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Sivakumaran Chandrasekaran 2012-9-10

Hi Andrei,Thanks. Your answer matches my requirement 90%.. for no.'2' your code works fine. Since there is a deviation in '1' it should not come. You can see the change in the value of 'e' when the value of 'a' is 1. Can you modify the code

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Answer 2

Adrian Dronca 2012-9-10

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I think you should consider using isequal() . The function works with single, double, string.

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Answer 3

Image Analyst 2012-9-10

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If they're integers, use ==, like

if a == e

if they're floating point, you need to check against a tolerance:

if abs(a-e) < 0.0001

See the FAQ for more info: http://matlab.wikia.com/wiki/FAQ#Why_is_0.3_-_0.2_-_0.1_.28or_similar.29_not_equal_to_zero.3F

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Answer 4

Sivakumaran Chandrasekaran 2012-9-12

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When you go through the first two rows, you can find that the change in the values. So, '1' should be omitted. There is no change in 3rd and 4th row.. 'e' value does not gets changed. So, we can consider 'e' .

How to do this??