How to sort matrix based on another matrix?

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K Venkatesh
K Venkatesh 2019-8-26
评论： K Venkatesh 2019-8-26
A=[3,2,1;8,3,1;6,4,2] and B=[5,9,2;9,2,1;8,7,4] Matrix A sort by row like A=[1,2,3;1,3,8;2,4,6] then based on A change values of B matrix like B=[2,9,5;1,9,2;4,7,8].

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采纳的回答

Stephen23
Stephen23 2019-8-26
>> A = [3,2,1;8,3,1;6,4,2]
A =
3 2 1
8 3 1
6 4 2
>> B = [5,9,2;9,2,1;8,7,4]
B =
5 9 2
9 2 1
8 7 4
>> [A,X] = sort(A,2);
>> for k = 1:size(X,2), B(k,:) = B(k,X(k,:)); end
>> A
A =
1 2 3
1 3 8
2 4 6
>> B
B =
2 9 5
1 2 9
4 7 8

更多回答（1 个）

Rik
Rik 2019-8-26
Assuming you made a small typo in your B_out:
A=[3,2,1;8,3,1;6,4,2];
B=[5,9,2;9,2,1;8,7,4];
for row=1:size(A,1)
[A(row,:),order]=sort(A(row,:));
B(row,:)=B(row,order);
end
clc,disp(B)

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