Infinite for loop getting stuck. Creating a new column containing a variable.

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nskel
nskel 2019-8-26
评论： Andrei Bobrov 2019-8-30
Hi, I am trying to generate a new column variable within a table which is conditional on 2 other values. The for loop I am using to generate it is getting stuck, however. It is generating the right values for me but just gets stuck and goes through the column over and over again. Any help would be appreciated:
data.signal = zeros(size(data.NAPMPMIIndex));
for indx=1:numel(data.NAPMPMIIndex)
if(data.NAPMPMIIndex(indx) > 50 & data.AboveMA(indx)> 0.5)
data.signal(indx) = 0.5
elseif(data.NAPMPMIIndex(indx) > 50 & data.AboveMA(indx)< 0.5)
data.signal(indx) = -0.5
elseif(data.NAPMPMIIndex(indx) < 50 & data.AboveMA(indx)> 0.5)
data.signal(indx) = 1
else
data.signal(indx) = -1;
end
end
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Adam Danz
Adam Danz 2019-8-29
I ran the code in your question using the data attached to your comment above. The loop is not getting stuck nor is it repeating the same column as you described. The loop runs as it should.
To confirm that, run this version below. The the only differences are
  • semicolons are used to suppress unnecessary output.
  • a counter "c" is used to count each iteration of the for-loop and the count is displayed so you can visually confirm that the loop has the expected 714 iterations.
load spxpmi2
data.signal = zeros(size(data.NAPMPMIIndex));
c = 0;
for indx=1:714
c = c+1;
disp(c)
if(data.NAPMPMIIndex(indx) > 50 & data.AboveMA(indx)> 0.5)
data.signal(indx) = 0.5;
elseif(data.NAPMPMIIndex(indx) > 50 & data.AboveMA(indx)< 0.5)
data.signal(indx) = -0.5;
elseif(data.NAPMPMIIndex(indx) < 50 & data.AboveMA(indx)> 0.5)
data.signal(indx) = 1;
else
data.signal(indx) = -1;
end
end
nskel
nskel 2019-8-29
ah, thanks very much.
I'm quite new to this but that is very much a rookie error
:-)

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Andrei Bobrov
Andrei Bobrov 2019-8-27
kk = [data.NAPMPMIIndex > 50, data.AboveMA > .5];
g = findgroups(kk(:,1),kk(:,2));
a = [-1;1;-.5;.5];
data.signal = a(g);
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