Related to Matlab Step Comment
2 次查看(过去 30 天)
显示 更早的评论
Hello, I have some question about Step resoponse Comment,
once, I want to plot about open loop system only use Transfer function,
For example for 1/(s+3) sytem, when I plot,
G = tf(1, [1,3])
step(G)
then the Final value of step response is 0.333, So Steady - State error around 0.667
When calculate steadt-state error is fisrt ordher system, We use 1/(1+Kp),
So in this system, Kp = 1/3, So Ess have to be 0.75.
Why is that differenet ??
0 个评论
采纳的回答
David Wilson
2019-8-27
You are possibly confusing the closed loop response with the open loop. The closed loop gain is 1/4, so the error is 1-1/4 = 3/4.
>> Gcl = feedback(G,1);
>> step(Gcl)
>> dcgain(Gcl)
ans =
0.2500
更多回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Dynamic System Models 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!