problem in my matlab code 'Index in position 1 exceeds array bounds (must not exceed 1)'

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brahmi ibtissem
brahmi ibtissem 2019-8-27
评论： brahmi ibtissem 2019-9-1
Hello everyone,
please how can i solve this problem:Index in position 1 exceeds array bounds (must not exceed 1).
Error in Sphere (line 51)
SinrC(i,j)=Pcellular(i,j)*calculate_gain(PositionsBS(1),PositionsBS(2), PositionsC(i,1),PositionsC(i,2)
)/(Icv+Noise);
Error in GeneticAlgorithm (line 11)
population.Chromosomes(i).fitness = obj( population.Chromosomes(i).Gene(:) );
Error in Main (line 50)
[BestChrom] = GeneticAlgorithm (M , N, MaxGen , Pc, Pm , Er , Problem.obj , visualization).
This is the code where i have SinrC(i,j):
throughputC=zeros(C);
SinrC=zeros(C,RB);
for i=1:C
Icv=0;
for j=1:RB
if binc(i,j)==1
for v=1:V
if binv(v,j)==1
Icv=Icv+Pv(v,j)*calculate_gain(PositionsBS(1),PositionsBS(2), PositionsV(v,1),PositionsV(v,2) );
end
end
SinrC(i,j)=Pcellular(i,j)*calculate_gain(PositionsBS(1),PositionsBS(2), PositionsC(i,1),PositionsC(i,2) )/(Icv+Noise);
throughputC(i)= throughputC(i)+W*log2(1+ SinrC(i,j));
end
end
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回答（2 个）

Walter Roberson
Walter Roberson 2019-8-29
You define PositionsC as a row vector but you access it as a column vector.
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brahmi ibtissem
brahmi ibtissem 2019-8-29
I still have this problem
Matrix dimensions must agree.
Error in Sphere (line 89)
c=a+b;
Error in GeneticAlgorithm (line 11)
population.Chromosomes(i).fitness = obj( population.Chromosomes(i).Gene(:) );
Error in Main (line 51)
[BestChrom] = GeneticAlgorithm (M , N, MaxGen , Pc, Pm , Er , Problem.obj , visualization)
Walter Roberson
Walter Roberson 2019-8-29
c=a+b does not appear in the code you posted, so we can only make guesses about it.
One of my guesses is that you are using R2018a or earlier.

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brahmi ibtissem
brahmi ibtissem 2019-8-29
THis is the code of c=a
=b
a=sum(throughputV);
b=sum(throughputC);
c=a+b;
I calculate throughputC and throughputV by using there instructions:
SinrC=zeros(C,RB);
for i=1:C
Icv=0;
for j=1:RB
if binc(i,j)==1
for v=1:V
if binv(v,j)==1
Icv=Icv+Pv(v,j)*calculate_gain(PositionsBS(1),PositionsBS(2), PositionsV(v,1),PositionsV(v,2) );
end
end
SinrC(i,j)=Pcellular(i,j)*calculate_gain(PositionsBS(1),PositionsBS(2), PositionsC(i,1),PositionsC(i,2) )/(Icv+Noise);
throughputC(i)= throughputC(i)+W*log2(1+ SinrC(i,j));
end
end
if throughputC(i)<SINRcth
constraintSatified=false;
end
end
throughputV=zeros(V);
SinrV=zeros(V,RB);
for v=1:V
Ivc=0;
for j=1:RB
if binv(i,j)==1
for c=1:C
if binc(c,j)==1
Ivc=Ivc+Pcellular(i,j)*calculate_gain(PositionsC(i,1),PositionsC(i,2), PositionsV(v,1),PositionsV(v,2) );
end
end
SinrV(v,j)=Pv(v,j)*calculate_gain(PositionsV(v,1),PositionsV(v,2),PositionsC(c,1),PositionsC(c,2) )/(Ivc+Noise);
throughputV(v)= throughputV(v)+W*log2(1+ SinrV(v,j));
disp( throughputV(v));
end
end
if throughputV(v)< SINRvth
constraintSatified=false;
end
end
  2 个评论
Walter Roberson
Walter Roberson 2019-8-29
Fishing through your postings as you do not show all of your code in one place, we see the lines
C=2;
V=3;
throughputC=zeros(C);
throughputV=zeros(V);
So throughputC is 2 x 2 and sum(throughputC) would be 1 x 2. Meanwhile throughputV is 3 x 3, and sum(throughputV) would be 1 x 3. You cannot add a 1 x 2 vector and a 1 x 3 vector.
I refer back to my first response,
I note by the way that you refer to throughputC(i) with a single subscript, after having defined throughputC=zeros(C ) . zeros(C ) defines a CxC matrix, equivalent to zeros(C,C) . This would not cause any problem in the part of the code you posted, but could potentially cause a problem in other parts of your code.
If you want a 1 x C vector, then you should be using zeros(1,C) not zeros(C )

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