Placing a constant through a column
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Imagine this
A=(1:30)';
B=(31:60)';
C=(61:90)';
D=[A B C];
S = numel(B);
xx = reshape(B(1:S - mod(S, 3)), 3, []);
BB = sum(xx, 1).' / 3;
F=[A B C BB];
You will notice F is not possible because BB has just 10 variables (Dimensions of arrays being concatenated are not consistent.)
What I need to do is make each value in BB constant for 3 rows so that F can become possible.
采纳的回答
madhan ravi
2019-8-28
repmat(BB,3,1)
3 个评论
DARLINGTON ETAJE
2019-8-28
madhan ravi
2019-8-28
编辑：madhan ravi
2019-8-28
Use:
repelem(BB,3)
DARLINGTON ETAJE
2019-8-28
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