Find series of maxima of array (and matrix) within blocks of size n

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Erez
Erez 2019-8-30
评论： Erez 2019-8-30
I have a simple problem, and it's, perhaps, less simple extension:
  1. I have an array A=[1 2 5 1 0 0 5 0 1 2 4 0 5 3 2 0 1 0 0 5] (all positive). How do I produce a vector B, which contains the maxima of, say, blocks of n=5 within A?
Namely, I want to produce B=[5 5 5 5].
2. I have a matrix: A=[1 2 5 1 0 0 5 0 1 2 4 0 5 3 2 0 1 0 0 5; 1 2 5 1 0 0 7 0 1 2 4 0 7 3 2 0 1 0 0 5; 1 2 5 1 0 0 5 0 1 2 4 0 5 3 2 0 1 0 0 5;] . Now, I want to get the matrix: C=[5 5 5 5; 5 7 7 5; 5 5 5 5] .
Can these two tasks be achomplished with a single procedure, without using loops?
Thanks!

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采纳的回答

Ted Shultz
Ted Shultz 2019-8-30
编辑：Ted Shultz 2019-8-30
You could use rehsape and max:
[reshape(max(reshape(A',5,[])), [], size(A,1))]'
Test:
A=[1 2 5 1 0 0 5 0 1 2 4 0 5 3 2 0 1 0 0 5]
[reshape(max(reshape(A',5,[])), [], size(A,1))]'
A=[1 2 5 1 0 0 5 0 1 2 4 0 5 3 2 0 1 0 0 5; 1 2 5 1 0 0 7 0 1 2 4 0 7 3 2 0 1 0 0 5; 1 2 5 1 0 0 5 0 1 2 4 0 5 3 2 0 1 0 0 5;]
[reshape(max(reshape(A',5,[])), [], size(A,1))]'
ans =
5 5 5 5
ans =
5 5 5 5
5 7 7 5
5 5 5 5

更多回答（1 个）

Bruno Luong
Bruno Luong 2019-8-30
编辑：Bruno Luong 2019-8-30
maxfun = @(A) squeeze(max(reshape(A,size(A,1),5,[]),[],2));
A = [1 2 5 1 0 0 5 0 1 2 4 0 5 3 2 0 1 0 0 5]
B = maxfun(A)
A = [1 2 5 1 0 0 5 0 1 2 4 0 5 3 2 0 1 0 0 5; 1 2 5 1 0 0 7 0 1 2 4 0 7 3 2 0 1 0 0 5; 1 2 5 1 0 0 5 0 1 2 4 0 5 3 2 0 1 0 0 5]
C = maxfun(A)
  1 个评论
Erez
Erez 2019-8-30
Awsome solution! I can't formally accept two solutions on this website, so I'll "accept" the first (arbitrarily). But this solution of yours works just as great. Thanks!

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