Going from structure to matrix

6 次查看(过去 30 天)
So I'm trying to dynamically solve a matrix and have it so I can reuse it next loop however solve seems to return a structure that I can't dynamically cast back into a matrix.
The only code I've found to do it dynamically fails for reason "CELL2MAT does not support cell arrays containing cell arrays or objects."
%Matlab solver test
NumberOfMasses = 20;
lamda = sym('lamda',[NumberOfMasses NumberOfMasses]);
test = lamda * eye(NumberOfMasses,NumberOfMasses);
eqn = lamda * eye(NumberOfMasses,NumberOfMasses) == eye(NumberOfMasses,NumberOfMasses)*2;
ans = solve(eqn,lamda);
cell2mat(struct2cell(ans))%needs to be a matrix for next loop
Is there something I'm missing to Dynamically cast "ans" back to a matrix? (Preferably without writing code that dynamically builds strings and runs getfield() on the struct)

采纳的回答

madhan ravi
madhan ravi 2019-9-1
Why not use struct2array() ? Note: Don’t Name a variable named ans .
  5 个评论
Dion Richardson
Dion Richardson 2019-9-1
编辑:Dion Richardson 2019-9-1
I'm prototyping mathematical functions that I want to later run in C++. My issue is I'm not great at maths so I often make mistakes and change parts of my formula. This occasionally means that in some cases weird conditions come up. The loop time is about 20-30 seconds for some of my code (which is fine for prototyping).
Subs works perfectly! Thanks so much, never would've expected that to be the case.

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Mathematics 的更多信息

产品


版本

R2019a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by