question about sinc function

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ADNAN KIRAL
ADNAN KIRAL 2019-9-2
评论： KALYAN ACHARJYA 2019-9-2
hi how can i get this figure ?
Capture.PNG
i have used the following eq.
Capture2.PNG
by coding the following type;
but it did not work can u please help me with that ? i cannot get negative values. thanks.
t=-511*0.005:0.01:512*0.005;
u_1=3/2*(110*sinc(110*pi*t)-60*sinc(60*pi*t));
  2 个评论
Dimitris Kalogiros
Dimitris Kalogiros 2019-9-2
Hi Adnan
What exactly do want to plot ?
A sync(t) function ? Or function u(t) which you gave ?

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采纳的回答

KALYAN ACHARJYA
KALYAN ACHARJYA 2019-9-2
编辑：KALYAN ACHARJYA 2019-9-2
t=-linspace(-511*0.005,512*0.005,1000)
u_t=3*(sin(2*55*pi*t)-sin(2*30*pi*t))./(2*pi*t);
plot(u_t);
  10 个评论
显示 8更早的评论
Torsten
Torsten 2019-9-2
This doesn't help since you still divide by 0 at t=0.
If you divide out, you get what I wrote in my answer.
KALYAN ACHARJYA
KALYAN ACHARJYA 2019-9-2
@Torsten OK sir, thanks for rectifying me. I will update it.
Gratitude!

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更多回答（1 个）

Torsten
Torsten 2019-9-2
编辑：Torsten 2019-9-2
t = -511*0.005:0.005:512*0.005;
u_1 = 3/2*(110*sinc(110*t)-60*sinc(60*t));

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