Dealing with wrong input

43 次查看(过去 30 天)
Lars Morsink
Lars Morsink 2019-9-3
How do I avoid this error? I would like for users, if they enter a string instead of number to told "Those are not the instructions, please try again"
Screenshot 2019-09-03 at 12.40.08.png
  4 个评论
Rik
Rik 2019-9-3
Please post your code as code, not as a screenshot. You can find an explanation of the layout tools here.
Lars Morsink
Lars Morsink 2019-9-3
clc,
clear
Secret_Number = randi(100);
Attempts = 0;
Max_Attempts = 10;
Guess = -1; % The variable needs to be established to avoid an error in the 'while...end' loop and -1 guarantees that it is not equal to the secret number
disp (' ')
disp ('Instructions: Guess a number between 1 and 100. You have 10 guesses and a hint after each guess. Good luck!')
while (Attempts < Max_Attempts) && (Secret_Number ~= Guess)
disp (' ')
Guess = input('Please enter your guess: ');
Attempts = Attempts + 1;
if Secret_Number == Guess
disp (' ')
disp ('Congratulations! You guessed the secret number!')
Attempts
elseif (Guess > Secret_Number) && (Attempts < Max_Attempts);
disp (' ')
disp ('Hint: Guess lower')
else
disp (' ')
disp ('Hint: Guess higher')
end
end
if Attempts == Max_Attempts & (Secret_Number ~= Guess);
disp (' ')
disp ('Game Over! You ran out of guesses. Please play again.')
Secret_Number
end

请先登录,再进行评论。

回答(2 个)

Stephen23
Stephen23 2019-9-3
编辑:Stephen23 2019-9-3
str = '';
num = NaN;
while isnan(num)
num = str2double(input([str,'Enter a number: '],'s'));
str = 'Please try again! ';
end
And tested:
Enter a number: hello
Please try again! Enter a number: world
Please try again! Enter a number: 42

Nicolas B.
Nicolas B. 2019-9-3
编辑:Nicolas B. 2019-9-3
Okay, then I would use the exception catching method:
str = '';
num = NaN;
while isnan(num)
try
num = input('Please enter your guess: ');
catch
disp('You must give a valid number!');
num = NaN;
end
end
  1 个评论
Rik
Rik 2019-9-3
That's also possible, although I think it would make slightly more sense to use Stephen's method, because then it also isn't possible to provide a variable name.
If you define a=9; before your loop, you can enter a in the prompt and it will pass the test. With Stephen's code, that is not possible.

请先登录,再进行评论。

类别

Help CenterFile Exchange 中查找有关 Creating and Concatenating Matrices 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by