Typing a script that uses incremental search to identify intervals.

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John wick 2019-9-4

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评论： John wick 2019-9-4

Typing a script that uses incremental search to identify intervals where the roots of the equation -260x^2 + 44x + 156 Are.

Take averages of the interval bounds as an approximation of the roots and make sure to use a step size that gives an absolute true error of the function value less than 0.01.

Your script should display the function value at the approximated roots.

So I try out these 2 code but some of them doesn’t work properly because it is larger than 0.01 or the code is quite long.

x1 = -1;
x2 = x1 +0.001;
while true 
y1= (-260.*x1.^2)+(44.*x1)+156;
y2= (-260.*x2.^2)+(44.*x2)+156;
if (y1>0 && y2<0) || (y1<0 && y2>0)
break
end
x1 = x1 + 0.001;
x2 = x2 + 0.001;
end
root1 = (x1+x2)./2;
x3 = x1 + 0.001;
x4 = x2 + 0.001;
while true
y3= (-260.*x3.^2)+(44.*x3)+156; 
y4= (-260.*x4.^2)+(44.*x4)+156;
if (y3>0 && y4<0 ) || (y3<0 && y4>0)
break
end
x3 = x3 + 0.001;
x4 = x4 + 0.001;
end
root2 = (x3+x4)./2;
root1
root2

This is the another short one

f = @(x) ((-260.*x.^2)+(44.*x)+156);
x = [0:0.01:1];
%h = 0.01
disp(f(x))

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darova 2019-9-4

Which one is bad?

John wick 2019-9-4

The first one give the result but it's quite long. Feel like it could be simplify. The second one is short and simple but it display more than it needed

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