Creating a matrix having repeating elements

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Rengin
Rengin 2019-9-4
评论： Rengin 2019-9-4
% Dear users,
% Assume that I have a A matrix having the size of 5x5 and in the end;
% I want to get A=[1 -1 0 0 0; 1 -1 0 0 0; 0 1 -1 0 0; 0 1 -1 0 0; 0 0 1 -1 0]
% What is the easiest way to do it?
% Thanks in advance
  6 个评论
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Bruno Luong
Bruno Luong 2019-9-4
OK here is different and still simple:
A=[1 -1 0 0 0; 1 -1 0 0 0; 0 1 -1 0 0; 0 1 -1 0 0; 0 0 1 -1 0]+0
The point is your question is not well formulated
Rengin
Rengin 2019-9-4
Thanks but I was still be able to get my answer. It works perfectly fine.

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Andrei Bobrov
Andrei Bobrov 2019-9-4
编辑：Andrei Bobrov 2019-9-4
A = kron(eye(5),[1;1])+kron(diag(-ones(4,1),1),[1;1]);
out = A(1:5,:);
or
n = 1:5;
A = repmat([1,-1,0,0,0],5,1);
out = A(mod(repmat(n,5,1) - ceil(n(:)/2),5)*5 + n(:));

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