Anomalous histogram for small argument

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Gordon Edwards
Gordon Edwards 2019-9-6
评论： Gordon Edwards 2019-9-7
Running the following code from the command line with c = 1e-15 or greater leads to a normal histogram
c = 1e-15; figure; histogram(c * rand(100,1))
histogram1.JPG
Running the following code with c = 1e-16 or less leads to an incorrect histogram
c = 1e-16; figure; histogram(c * rand(100,1))
histogram2.JPG
The problem appears also in apps when the histogram function is invoked.
Is this a bug?
Gordon

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采纳的回答

Bruno Luong
Bruno Luong 2019-9-7
编辑：Bruno Luong 2019-9-7
Yes it is a BUG. I chase back and in the file
C:\Program Files\MATLAB\R2019a\toolbox\matlab\datafun\+matlab\+internal\+math\binpicker.m
line #20 (R2019a)
there is a test
if xrange > max(sqrt(eps(xscale)), realmin(class(xscale)))
To me the correct test should be (without sqrt)
if xrange > max(eps(xscale), realmin(class(xscale)))
Now if I change this line and rerun the code
c = 1e-16; figure; histogram(c * rand(100,1))
it produces correct plot
More seriously, the function binpicker is called by HISTCOUNT. So HISTCOUNT is also buggy. Not only plotting but calculation might be wrong.
  1 个评论
Gordon Edwards
Gordon Edwards 2019-9-7
Thanks for your reply.and I believe that you have spotted the error in function binpicker.Since eps(x) ~ 1e-16*x, and in my case xscale and xrange are nearly equal, the condition that
xrange > sqrt(eps(xscale))
leads to xrange >~ 1e-16 which is what I find.

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更多回答（1 个）

Jackson Burns
Jackson Burns 2019-9-7
Here's a similar question asked a few years ago which was never really solved either. This comment may be your best approach, but I would reccomend just bringing the values to unity with something like this:
c = 1E-16;
figure
mydata = c * rand(100,1);
histogram(mydata./max(mydata))
You could then modify the xticklabels to match whatever the original values were.

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