Permutations using multiple vectors of different lengths
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I am trying to sum values of all permutations of values from multiple matrices of different lengths, and cannot find a way to use perms or for loops to do it.
v1=[10,600,800];
v2=[6,13];
v3=[5,2];
v4=[10,15,22,6];
v5=[12,5];
I want each matrix to contribute one (and only one) value to the permutation. Ultimately, I'm looking for a list that shows something like the following:
10+6+5+10+12=43
10+6+5+10+5=36
10+6+5+15+12=45
...
800+13+2+6+5=826
Even better would be if I could figure out how to get it to show the indexes used for each one as follows:
(1)+(1)+(1)+(1)+(1)=43
(1)+(1)+(1)+(1)+(2)=36
(1)+(1)+(1)+(2)+(1)=45
...
(3)+(2)+(2)+(4)+(2)=826
Any help is greatly appreciated. Thank you.
2 个评论
John D'Errico
2019-9-9
编辑：John D'Errico
2019-9-9
help ndgrid
Think about what it does.
Robert Rieke
2019-9-9
采纳的回答
David Hill
2019-9-9
If the number of matrixes does not change (in this case 5 different maxtrixes,a b,c,d,e), for-loops could be used this way:
output=zeroes(1,length(a)*length(b)*length(c)*length(d)*length(e));
count=1;
for i1=a
for i2=b
for i3=c
for i4=d
for i5=e
output(count)=i1+i2+i3+i4+i5;
count=count+1;
end
end
end
end
end
2 个评论
David Hill
2019-9-9
If you want indexes, this output produces each index used to obtain the sum.
function output = sumPermMatrixes(a,b,c,d,e)
output=zeros(length(a)*length(b)*length(c)*length(d)*length(e),6);
count=1;
for i1=1:length(a)
for i2=1:length(b)
for i3=1:length(c)
for i4=1:length(d)
for i5=1:length(e)
output(count,:)=[i1,i2,i3,i4,i5,a(i1)+b(i2)+c(i3)+d(i4)+e(i5)];
count=count+1;
end
end
end
end
end
end
Robert Rieke
2019-9-9
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