Why does setdiff answer depend on order of arguments?
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>>bob = {'a','b','c'};
>>bill = {'a','b','c', 'd','e'}
As expected,
>>A = setdiff(bill,bob)
A =
'd' 'e'
BUT
>> B = setdiff(bob,bill)
B =
Empty cell array: 1-by-0
WHY??
采纳的回答
Steven Lord
2019-9-9
0 个投票
Were you expecting the output to contain elements that are only in one of the inputs but not both? That's not what setdiff does. If that is what you want to do, use setxor instead.
2 个评论
Brian Wilson
2019-9-10
It is worth nothing that MATLAB setdiff follows the standard mathematical definition of "set difference", which is defined as A\B (i.e the elements of A that are not in B):
etc.
Although this is the accepted mathematical definition, the term "set difference" is rather ambiguous in common english. It would be nice if it used terms whose meaning was obvious.
更多回答（2 个）
madhan ravi
2019-9-9
编辑：madhan ravi
2019-9-9
bob not in bill (nothing unique all elements of bob belong to bill)
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