could anyone help me to solve the issue in the following code

Question

jaah navi 2019-9-10

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/479653-could-anyone-help-me-to-solve-the-issue-in-the-following-code

评论： jaah navi 2019-9-10

code:

a=[0.0022;
   0.0922;
   0.0146;
   0.2549];
[m,n]=size(a);
differences = bsxfun(@minus,reshape(a,m,1,n),reshape(a,1,m,n));
v = nonzeros(differences');
newmat = reshape(v,3,4)';
val = max(newmat');
V=val';

the above code executes and gives me the result.

but when i run the code below

a=[0.0022  0.0021;
   0.0922  0.0938;
   0.0146  0.0143;
   0.2549  0.2509];
[m,n]=size(a);
differences = bsxfun(@minus,reshape(a,m,1,n),reshape(a,1,m,n))
v = nonzeros(differences');
newmat = reshape(v,3,4)'
val = max(newmat')
V=val'

I am error stating Error using '

Transpose on ND array is not defined. Use PERMUTE instead.

Error in (line 20)

v = nonzeros(differences');

Could anyone please help me on it.

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madhan ravi 2019-9-10

Desired result?

jaah navi 2019-9-10

在 MATLAB Online 中打开

V=[ -0.0124   0.0122;
0900   0.0917;
0124    0.0122;
2527    0.2488]

This was the result with respect to matrix size of (4,2)

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Answer 1

Raj 2019-9-10

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https://ww2.mathworks.cn/matlabcentral/answers/479653-could-anyone-help-me-to-solve-the-issue-in-the-following-code#answer_391159

编辑：Raj 2019-9-10

在 MATLAB Online 中打开

"Could anyone please help me on it" - You have not exactly mentioned what help are you looking for. Your error message is self explanatory. In first case, the differences is a 4x4 2D matrix and transpose works on that. In second case, the differences is a 3D matrix with dimensions as 4x4x2 so transpose will not work here and you have to use 'permute'. If how to use permute is your doubt then see details here. Any other specific issues here?

Use this for your desired result:

a=[0.0022  0.0021;
   0.0922  0.0938;
   0.0146  0.0143;
   0.2549  0.2509];
[m,n]=size(a);
differences = bsxfun(@minus,reshape(a,m,1,n),reshape(a,1,m,n))
v1 = nonzeros(differences(:,:,1)');
v2 = nonzeros(differences(:,:,2)');
newmat1 = reshape(v1,3,4)'
newmat2 = reshape(v2,3,4)'
val = [max(newmat1');max(newmat2')]
V=[val']

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Raj 2019-9-10

在 MATLAB Online 中打开

In case of large number of columns, you can define some cell arrays and loops like this:

a=[0.0022  0.0021;
   0.0922  0.0938;
   0.0146  0.0143;
   0.2549  0.2509];
[m,n]=size(a);
differences = bsxfun(@minus,reshape(a,m,1,n),reshape(a,1,m,n))
v=cell(1,n);
for ii=1:n
v(1,ii) = {nonzeros(differences(:,:,ii)')};
end
newmat=cell(1,n);
for ii=1:n
newmat(1,ii) = {reshape(cell2mat(v(1,ii)),3,4)'};
end
val=max((cell2mat(newmat(1,1)))');
for ii=2:n
val = [val ;max((cell2mat(newmat(1,ii)))')];
end
V=[val']