Method to compound daily data by n-days?

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Walter
Walter 2012-9-12
Given:
[1 2 3 4 5 6] and n = 1,
return [1, 2, 3, 4, 5, 6]
given n=2, return: [1*2, 3*4, 5*6]
given n=3, return: [1*2*3, 4*5*6]
given n=4, return [1*2*3*4]
given n=5, return [1*2*3*4*5]
given n=6, return [1*2*3*4*5*6]
not sure what to call this algorithm, but can anyone think of a clever way to do it?

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回答（2 个）

Yi Sui
Yi Sui 2012-9-12
function re = foo(x,n)
len = length(x);
seg = floor(len/n);
res = mod(len,n);
x2 = mat2cell(x,1,[ones(1,seg).*n res]);
re = cellfun(@prod,x2);
re = re(1:end-1);
Andrei Bobrov
Andrei Bobrov 2012-9-12
I = 1:6; % The initial array
out = nonzeros(prod(reshape([I,zeros(1,mod(-numel(I),n))],n,[])))';

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