Repeating array row n times with change of indexes

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Joanna Widzinska
Joanna Widzinska 2019-9-12
回答： Joanna Widzinska 2019-9-24
Hello everyone,
I have matrix of 1 minute data of the household load (5760x2, where 1st column reflects minutes and second the load). I need to transform data into seconds, where every row will be repeated 60 times with the change of indexes.
Ex.
1min x1 1 x1
2min x2 -----------------> 2 x1
... .....
5760min x5760 60 x1
61 x2
...
120 x2 etc.
I tried many different options and now I think it's involved in multiplying the matrices, but I can't solve this properly.
Can somebody help me? Thanks!

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采纳的回答

Shubh Sahu
Shubh Sahu 2019-9-18
Hello Jonna,
Let us suppose, the household data is in ‘a’, to repeat the number of rows repelem function is used:
u(:,2) = repelem(a(:,2),[60]);
u(:,1)=1:(5760*60);
for more information regarding repelem refer the following link:
https://www.mathworks.com/help/matlab/ref/repelem.html?searchHighlight=repeat&s_tid=doc_srchtitle
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Shubh Sahu
Shubh Sahu 2019-9-19
Have a look on this, may it explains
clc;
clear all;
close all;
a=[1,5;2,7;3,8];% take a 3*2 matrix
u(:,2) = repelem(a(:,2),[60]);
u(:,1)=1:(size(a,1)*60);

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Joanna Widzinska
Joanna Widzinska 2019-9-24
It worked! Thank you very much :)

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