Plotting circles in a for loop using a time step

Question

Hannah Haynie 2019-9-16

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/480613-plotting-circles-in-a-for-loop-using-a-time-step

评论： Hannah Haynie 2019-9-23

Hi there,

I am looking for enlightenment and I am not even sure if this will make sense, but I am trying to plot some cells to help me with reducing costs in a Biology lab. I would like to create a Matlab for loop that plots circles with origin on the circumference of the original plotted circle this will happen at each timestep. This is to mimic cell division.

My original code is:

clear all 
close all
clc
 
for k = 1:5 %numberofruns
    
x0=2;
y0=1;
r=1;
theta=-pi:0.01:pi;
x=r*cos(theta)+x0;
y=r*sin(theta)+y0;
plot(x,y)
hold on
scatter(x0,y0,'or')
% axis square 
% ----------------------------------------
% divide your circle to n sectors
n=2
tet=linspace(-pi,pi,n+1)
xi=r*cos(tet)+x0
yi=r*sin(tet)+y0
 
plot(xi,yi)
 
x0=1;
y0=1;
r=1;
theta=-pi:0.01:pi;
x=r*cos(theta)+x0;
y=r*sin(theta)+y0;
plot(x,y)
hold on
scatter(x0,y0,'or')
% axis square 
% ----------------------------------------
% divide your circle to n sectors
n=2
tet=linspace(-pi,pi,n+1)
xi=r*cos(tet)+x0
yi=r*sin(tet)+y0
 
plot(xi,yi)
 
% for k=1:numel(xi)
% plot([x0 xi(k)],[y0 yi(k)])
% hold on
% end
 
x0=3;
y0=1;
r=1;
theta=-pi:0.01:pi;
x=r*cos(theta)+x0;
y=r*sin(theta)+y0;
plot(x,y)
hold on
scatter(x0,y0,'or')
% axis square 
% ----------------------------------------
% divide your circle to n sectors
n=2
tet=linspace(-pi,pi,n+1)
xi=r*cos(tet)+x0
yi=r*sin(tet)+y0
 
plot(xi,yi)
 
pause(1) %timeinsec
 
shg
end