Error: Function definition not supported in this context. Create functions in code file.

2019 9 19
1 个回答
更新时间：2019 11 22
2 次查看（30 天）

0 个投票

My function with code prompt being user input.
function [v]=Deflection_Caabt(x)
if (0 < prompt) && (prompt <= 120)
(1/(3.19*10e9)) * 800*xe3 - 13.68 * 10e6 - 2.5*xe4;
else
(120 < prompt) && (prompt <= 240);
(1/(3.19*10e9))*800*xe3-(13.68*10e6)-2.5*xe4+2.5*(x-120)*e4;
Elseif
(240 < prompt) && (prompt <= 360);
(1/(3.19*10e9))*(800*xe3-(13.68*10e6)-2.5*x^4+2.5*x-120e4+600*(x-240)*e3);
end

请先登录，再回答此问题。

回答（1 个）

Jyothis Gireesh
Jyothis Gireesh 2019-11-22

0 个投票

One method may be to include an input statement using “input()” to accept the value of “prompt”. Another possible workaround is to accept the user input outside the function and to pass it as an argument to the function.

类别

在 帮助中心 和 File Exchange 中查找有关 Matched Filter and Ambiguity Function 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by