could anyone help me how to display all the numbers inaddition to the numbers present.

Question

jaah navi 2019-9-19

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回答： Stephen23 2019-9-19

采纳的回答： Stephen23

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I a having a system with maximum number of users to be 6.

A =[1 2;

1 3;

2 5;

2 4;

3 5;

4 6

4 5]

In each row i can get only two numbers out of 6.

But i want to display all the numbers in each row of the matrix in the following manner

[1 2 3 4 5 6;

1 3 2 4 5 6;

2 5 1 3 4 6;

2 4 1 3 5 6;

3 5 1 2 4 6;

4 6 1 2 3 5;

4 5 1 2 3 4]

So I want to reshape the matrix A inorder to get the above matrix

Could anyone please help me on this.

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Answer 1

Stephen23 2019-9-19

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>> A = [1,2;1,3;2,5;2,4;3,5;4,6;4,5]
A =
   2
   3
   5
   4
   5
   6
   5
>> F = @(v)[v,setdiff(1:6,v)];
>> M = cell2mat(cellfun(F,num2cell(A,2),'uni',0))
M =
   2     3     4     5     6
   3     2     4     5     6
   5     1     3     4     6
   4     1     3     5     6
   5     1     2     4     6
   6     1     2     3     5
   5     1     2     3     6

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Answer 2

darova 2019-9-19

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I'd divide you task in several steps:

Use for loop to consider each row separately
Use ismember() to identificate which numbers (1:6) are members of a current row
Add to the current row number that are not members

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Adam 2019-9-19

Why are you using randperm? setdiff should return 4 values for each row, which should be assigned (in the order they are returned, so far as I can see from what you want) as columns 3 to 6 or that row of the result matrix.

jaah navi 2019-9-19

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could you please help me to get the following result

[1     2     3    4    5    6;
   3     2    4    5    6;
   5     1    3    4    6;
   4     1    3    5    6;
   5     1    2    4    6;
   6     1    2    3    5;
   5     1    2    3    4]