A number contain in a series.

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Silpa K 2019-9-19

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评论： Silpa K 2019-9-20

I have a series 's'

s=(1:1,2:end)

I find its subsequences like

a=s(1:30)
b=s(30:60)
c=s(60:90)
d=s(90:120)
e=s(120:150)
f=s(150:180)
j=s(180:210)

h=s(210:250)

and I have a set of points 'k'.

I need to check any of the subsequence contain any points of the K.If it contain I need to add those subsequence into a variable 'A'.How can I do this.Please help me.

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Guillaume 2019-9-19

s = (1:1, 2:end)

is not valid matlab syntax. So, the first problem with your question is we don't really not what your series is.

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回答（1 个）

thoughtGarden 2019-9-19

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编辑：thoughtGarden 2019-9-20

You haven't provided enough information to be certain of what you want, but makeing some assumptions, this should work.

clear;clc;
% "series" s, which is an array
s = 1:1:250;
% Build "subsequences"
for ii = 1:7
    subSequence(ii,:) = s((ii-1)*30 + 1:ii*30);
end
% Build "set of points 'k'"
k = randi(1000,1,10);
% A will contain all subsequences that contain any of the values of k
A = [];
% In each loop, determine if there is any overlap betweent he subsequence
% and the variable k. If there is, add the subsequency to the variable A.
% Otherwise, move on to the next subsequence.
for ii = 1:length(subSequence(:,1))
    
    if(intersect(subSequence(ii,:),k))
        A(end+1,:) = subSequence(ii,:);
    else
        %do nothing...
    end
end
% Disp A, which in the case of this script might be empty as k is random
% values...
disp(A)

This builds an array containing all the subsequences that contain any values found in k. If that is what you are looking for, this works.

After looking at your code, it looks like you are trying to find the subsequences that contain any of the max 14 values of the variable sec. If you use the template above (note I removed the cells as it appears you have constant and equal length subsequences) you can solve the problem. I have not used your sequencial lettering of variables because in general this is poor practice (what if you your subsequence number grows in the future?). However, if k is some array containing values that are also present in the subsequences, the for loop will find them.

d = xlsread('FaceFour_TRAIN.xlsx')
s = d(1:1,2:end );
fa = movstd(s,20 );
secarray = movstd(fa,20 ) ;
sec = secarray(secarray>.04 );
k=maxk(sec,14);
% Build "subsequences"
for ii = 1:7
    subSequence(ii,:) = s((ii-1)*30 + 1:ii*30);
end
% A will contain all subsequences that contain any of the values of k
A = [];
% In each loop, determine if there is any overlap betweent he subsequence
% and the variable k. If there is, add the subsequency to the variable A.
% Otherwise, move on to the next subsequence.
for ii = 1:length(subSequence(:,1))
    
    if(intersect(subSequence(ii,:),k))
        A(end+1,:) = subSequence(ii,:);
    else
        %do nothing...
    end
end
% Disp A, which in the case of this script might be empty as k is random
% values...
disp(A)