unique values inside a matrix

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Hello,
Assuming i have a matrix like this m=
1 30
1 20
1 20
1 20
2 30
2 28
2 28
... ...
i want it to be like this:
1 30
1 20
2 30
2 28
PS: THE MATRIX IS HUGE CONSISTING OF 11000 ROWS AND 9 COLUMNS
unique is not working since it has it's taking a unique value of all, for example if i apply it for the second column it will take 28 for 1 and not for 2
thank you in advance

采纳的回答

Star Strider
Star Strider 2019-9-21
编辑:Star Strider 2019-9-21
Try this:
A = [1 30
1 20
1 20
1 20
2 30
2 28
2 28];
Out = unique(A, 'rows', 'stable')
producing:
Out =
1 30
1 20
2 30
2 28
Experiment to get different results.
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更多回答(1 个)

Guillaume
Guillaume 2019-9-21
I'm not sure what you mean by unique is not working. You haven't explained the reasoning for going from your input to your output, but it does look like you want unique rows:
result = unique(m, 'rows')
With your demo data:
>> m = [
1 30
1 20
1 20
1 20
2 30
2 28
2 28];
>> unique(m, 'rows')
ans =
1 20
1 30
2 28
2 30
>> unique(m, 'rows', 'stable') %with stable to get the same order as your example
ans =
1 30
1 20
2 30
2 28
  5 个评论
Michel tawil
Michel tawil 2019-9-21
i can use this and it works well but i lose the cotents of the other colums
M=unique(C(:,1:2),'rows','stable');

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