How to integrate a plot over specified range?

Question

behzad 2019-9-22

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/481542-how-to-integrate-a-plot-over-specified-range

评论： Rik 2019-9-22

Hi everyone.

I want to integrate a plot over specified range. i have two seperate arrays i.e. x(t) and y(x) which i already have in a plot. now i want to integrate y(x) over x(t) from x(t1) to x(t2), the area under y(x) over this specified range.

To get a better view, let me elaborate with an example:

t = 0:0.1:2*pi;
x = sin(t);
y = cos(x);

Now the question is how to calculate ∫y.dx from x(t=1) to x(t=2).

best regards

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

MS 2019-9-22

1
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/481542-how-to-integrate-a-plot-over-specified-range#answer_392966

编辑：MS 2019-9-22

在 MATLAB Online 中打开

You can use the integral function to numerically integrate a function from xmin to xmax. Example:

% define functions 
fun_x = @(t) sin(t);
fun_y = @(x) cos(x);
% assign the time interval
t1 = 1;
t2 = 2;
% evaluate function x
xmin = feval(fun_x,t1);
xmax = feval(fun_x,t2);
% integrate
q = integral(fun_y,xmin,xmax);
disp (q);

>>> Output:

0.0434

Hope this helps.

4 个评论
显示 2更早的评论隐藏 2更早的评论

MS 2019-9-22

编辑：MS 2019-9-22

在 MATLAB Online 中打开

In this case, you may consider the integral as a summation of the sub-areas under the curve. For example, consider the following criteria. I'm using the functions to create the x and y vectors as an example, but you can import them (assuming you have the data points as you said).

% time vector
t=0:0.1:2*pi;
overall_total = length(t);
x_vector = zeros(1,overall_total);
y_vector = zeros(1,overall_total);
% create the arrays (or get them)
for i=1:overall_total
    x_vector(i) = sin(t(i));
    y_vector(i) = cos(x_vector(i));
end 
% select the points in the x_vector and the y_vector that belongs to the
% interval (t belongs to [t_min,t_max])
t_min = 1;
t_max = 2;
counter =1;
for i=1:overall_total
    if ((t(i)>=t_min) && (t(i)<=t_max))
        selected_x_vector(counter) = x_vector(i);
        selected_y_vector(counter) = y_vector(i);
        counter = counter + 1;
    end
end 
% calculate the sub areas and add them to the summation 
selected_total = length(selected_x_vector);
total_area_integral = 0;
for i=2:selected_total
    % difference between consecutive x points
    width = selected_x_vector(i) - selected_x_vector(i-1);
    % average of consecutive y points 
    length = (selected_y_vector(i) + selected_y_vector(i-1)) / 2;
    % calculate sub area 
    sub_area = width*length;
    % add sub area to summation 
    total_area_integral = total_area_integral + sub_area;
end
% result
disp(total_area_integral);

>>> Output:

0.0434

behzad 2019-9-22

I get the idea. It is nice and clean, very basic too. I think this solves the problem.

Very helpfull, thanks MS.

Rik 2019-9-22

It should be possible to replace your last loop with trapz.

请先登录，再进行评论。

Answer 2

Rik 2019-9-22

1
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/481542-how-to-integrate-a-plot-over-specified-range#answer_392967

编辑：Rik 2019-9-22

在 MATLAB Online 中打开

As you indicated with the tags, using trapz is also an option.

fun_x_of_t=@(t) sin(t);
fun_y_of_x=@(x) cos(x);
fun_y_of_t=@(t) fun_y_of_x(fun_x_of_t(t));
t=linspace(1,2,100);
x=fun_x_of_t(t);
y=fun_y_of_t(t);
trapz(x,y)

2 个评论
显示无隐藏无

behzad 2019-9-22

Thank you Rik.

I know i stated in second part of my question the functions are available as sin and cos. But what we can do in a situation that we have just data points in a plot and they are not known as common functions?

I appreciate you considering the question.

Rik 2019-9-22

As long as you have the xy paired data, you can use trapz. If you don't have x (or it is impossible to derive x from t) what you want is imposible.

请先登录，再进行评论。

How to integrate a plot over specified range?

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

采纳的回答

4 个评论
显示 2更早的评论隐藏 2更早的评论

更多回答（1 个）

2 个评论
显示无隐藏无

另请参阅

类别

标签

Community Treasure Hunt

How to integrate a plot over specified range?

0 个评论 显示 -2更早的评论隐藏 -2更早的评论

采纳的回答

4 个评论 显示 2更早的评论隐藏 2更早的评论

更多回答（1 个）

2 个评论 显示 无隐藏 无

另请参阅

类别

标签

Community Treasure Hunt

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

4 个评论
显示 2更早的评论隐藏 2更早的评论

2 个评论
显示无隐藏无