How can I implement this code several stages??

I want to compute 15 stages of the my output , my problem is in the second loop, is it correct?? i want to implement yi+1(n) = yi(n) * wi+1 ie: y1(n) is the first stage and so on...when i run it i get Index exceeds matrix dimensions. error in y(i+1,:)=y(i)*w(i+1,:);
also, how can i plot the fourth stage??? thank you for the help.
% w = estimated FIR filter
% y = output array y(n)
% x = input array x(n)
% d = desired array d(n), length must be same as x
% mu = step size
% M=order of the filter;
N=300;
n=1:N;
M=4;
d(n) = sin(0.2*pi*n);
sigma = 0.5;
v(n) =sigma*randn(1,N);
x(n)= d+v; N=length(x);
subplot(311); plot(d(n))
mu=0.01; subplot(312); plot(x(n))
w=zeros(1,M); w1=zeros(1,M);e=zeros(1,N);y=zeros(1,N);
for n=M:N
x1=x(n:-1:n-M+1);
y(n) = w*x1';
e = d(n)-y(n);
w = w +mu*e*x1;
w1(n-M+1,:)=w(1,:);
end
% I is number of stages
I=15;
for i=2:I
y(i+1,:)=y(i)*w(i+1,:);
end

8 个评论

M and d are undefined for starters...
Please provide the complete information (all input data) to get the exact solution.
Still not enough information.
We need a working example so we can run your code. There are missing variable values and the code in your comment above is not executable. To move forward, provide a functional code that you've tested and we can copy-paste into our environment.
We still can't run the code.
Unrecognized function or variable 'M1'.
Error in jff (line 18)
x1=x(n:-1:n-M1+1);
Sorry, it is typo. it is M not M1
M=4;
w=zeros(1,M);
okay so w is 1 x 4
w = w +mu*e*x1;
mu and e are scalars and x1 is 1 x 4, so w stays 1 x 4
I=15;
for i=2:I
y(i+1,:)=y(i)*w(i+1,:);
end
That asks for row number 2+1=3 of w, but w only has 1 row.
Is the second loop correct???? in my case:the future out put is dependent on the present out put and the future filter
How can it be correct when you are asking for multiple rows of w when w only has one row?

请先登录,再进行评论。

回答(0 个)

类别

帮助中心File Exchange 中查找有关 Communications Toolbox 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by