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Index exceeds matrix dimensions.

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Carlos Antonio Hernández Guerrero
评论： Carlos Antonio Hernández Guerrero 2019-9-24
I've been fixing this code, now i have a problem in line 29, that says "Index exceeds matrix dimensions." how can I fix it ?
%T=1/pi;
t=-pi:pi/99:pi;
A=2;
w0=(2.*pi)*(1./t);
f=A*sin(t)
f1=abs(f);
figure(1)
plot(t,f1)
%serie de fourier
%hold on
for n=1:2:40
y=f1+((2*A)/pi)*(sin(n*t)/n);
plot(t,y) ;pause(.2)
%hold off;
end
figure(2)
%fft
y2=f1+((2*A)/pi)*(sin(20*t)/20);
Fs=1500;
Ts=1./Fs;
L=1500;
tl=(0:L-1).*Ts;
y4=fft(y2);
P2=abs(y4./L);
P1=P2(1:L./2+1);
P1(2:end-1)=2*P1(2:end-1)
g= Fs*(0:(L/2))/L;
plot(handles.axes2,g,P1,'r')

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采纳的回答

Shubham Gupta
Shubham Gupta 2019-9-23
P2 is an array of dimesion 1x199 and L=1500. So, when you write :
P1=P2(1:L./2+1);
that means
P1 = P2(1:751);
So, indeces of P2 greater than 199 exceeds than it's maximum size of 199.
One way to correct this, will be to modify 'L' .
I hope it helps !
  1 个评论
Carlos Antonio Hernández Guerrero
Carlos Antonio Hernández Guerrero 2019-9-24
you're rigth, thank you so much, i already realized that it was something about the dimension but i can´t see where i had to modify, thanks

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