problems using && with dropdown list result
1 次查看(过去 30 天)
显示 更早的评论
hi!
S={'NH4Cl'; 'MgCl2'; 'CaCl2'; 'ZnCl2'; 'ZnSO4'; 'NaCl'};
>> str={'Choose the combinations of salts available'};
>> result=listdlg('Promptstring',str, 'ListSize', [100,100], 'ListString', S, 'SelectionMode', 'multiple');
>> if result==1&&result==3
disp('hei')
end
the error I get: Operands to the || and && operators must be convertible to logical scalar values. Donnt understand because the output from result is scalar and is should be possible to use && togehter with scalar outputs..
4 个评论
the cyclist
2019-9-24
Muazma,
The problem with your code is clear to me (and Adam). You have allowed the user to select multiple items. For example, they might select 'NH4Cl' and 'CaCl2'. In this case,
result = [1 3]
and you are trying to evaluate
[1 3]==1 && [1 3]==3
which is
[1 0] && [0 1] % these are logical vectors
These are not allowable operands for the short-circuit logical operators. The operands must each be a single scalar value.
What is not clear to me is what you want to happen in your if statement. Perhaps you could explain this more completely.
采纳的回答
the cyclist
2019-9-24
Here is what I think you want, based on your most recent comment:
if all(ismember([1 3],result))
disp('hei')
end
The if statement will be entered if the user's selections include 'NH4Cl' and 'CaCl2'.
0 个评论
更多回答(1 个)
the cyclist
2019-9-24
My best guess as to what you want is
if any(ismember(result,[1 3]))
disp('hei')
end
The if statement will be entered if the user's selections include 'NH4Cl' or 'CaCl2' (or both).
2 个评论
Guillaume
2019-9-24
Maybe the OP wants all instead of any. I.e all the selections must be NH4Cl or CaCl2
if all(ismember(result, [1 3]))
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Whos 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!