Sum of alternating series
15 次查看(过去 30 天)
显示 更早的评论
How do you find the sum of a series with alternate signs. I know how to find with same signs but not alternating. I have no idea where to start. For example, 1-(1/3)+(1/5)-(1/7)+(1/9)...-(1/1003) with the sum equaling to 0.7849~pi/4
*This is not a homework problem. This is a studying question for my upcoming exam. I am very new to matlab and do not know where to start.
0 个评论
采纳的回答
Star Strider
2019-9-27
N = 1003;
frc = (1./(1:2:N));
exv = (-1).^(0:numel(frc)-1);
ser = frc.*exv
ser_sum = sum(ser)
ser_sum =
0.784900155923366
0 个评论
更多回答(1 个)
jeewan atwal
2019-9-27
Please go through following link:
https://www.quora.com/Why-is-1-1-3-+-1-5-1-7-+-1-9-%CF%80-4
0 个评论
另请参阅
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!