how to assign the value to the matrix

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rupak katwal
rupak katwal 2019-9-28
编辑： rupak katwal 2019-10-1
I have the string suppose 'aB@2', Now i first i want to create the matrix with the character of these string.
λ a B @ 2
λ 0 a B @ 2
a 0 aa aB a@ a2
B 0 Ba BB B@ B2
@ 0 @a @B @@ @2
2 0 2a 2B 2@ 4
Now,i have the text file containing these strings
122 Ba@2
123 a@2B
144 2@Ba
From the first string 122 Ba@2, the character after the first space is:
Ba@2
i want to update the above matrix as
a 122 @ 2 2
0 aa aB 122 a2
0 122 BB B@ B2
0 @a @B @@ 122
0 2a 2B 2@ 4
From this way i want update the above matrix along with the list of string in text file.
  1 个评论
Stephen23
Stephen23 2019-10-1
@rupak katwal: please show the expected output matrix for the example data you provide in your question.

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回答（1 个）

Dinesh Yadav
Dinesh Yadav 2019-10-1
I am attaching a code which helps you generate a cell array of how you want your matrix to look like. It’s a pseudo code, you can make changes to it to generalize it as you want.
After you have generated the cell matrix compare each element of cell matrix like if element(i,j)==”B”then replace it with 122 and so on for the other elements too.
z = ['a','B','@','2'];
z1 = ['a','B','@','2']; %copy of above array for simplicity of use
arr = cell(5,5);
for i = 1:5
for j=1:5
if(j==1)
arr{i,j}=0;
elseif (j~=1 && i==1)
arr{i,j}= z(j-1);
else
arr{i,j}=strcat(z(i-1),z1(j-1));
end
end
end
  1 个评论
Stephen23
Stephen23 2019-10-1
编辑：Stephen23 2019-10-1
Note that [] is a concatenation operator, so
z = ['a','B','@','2'];
is just a complex way of defining this character vector:
z = 'aB@2';

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