finding duplicate number and adjacent row value
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Suppose I have a matrix of values
v = [1 4; 1 5; 2 4; 2 4; 2 5; 2 5; 3 4; 3 7]
in column one the numbers are consecutive but with repetition, how can I find only the first numbers and corresponidng number in the other column, put them in a new matrix (v')? The new matrix should be like this from my example:
v'= [1 4; 2 4; 3 4]
I hope I am clear enough
Cheers
Sobhan
1 个评论
Azzi Abdelmalek
2012-9-16
编辑：Azzi Abdelmalek
2012-9-16
what if v= [1 4; 1 5; 2 4; 2 4; 2 5; 2 5; 3 4; 3 7;1 5;1 6]?
采纳的回答
Azzi Abdelmalek
2012-9-16
v = [1 4; 1 5; 2 4; 2 4; 2 5; 2 5; 3 4; 3 7]
idx=diff(v(:,1))
v1=[];
if idx(1)==0
v1=[v1;v(1,:)]
end
for k=2:length(idx)
if idx(k)==0 & idx(k-1)~=0
v1=[v1; v(k,:)]
end
end
更多回答（1 个）
Wayne King
2012-9-16
编辑：Wayne King
2012-9-16
[~,iv] = unique(v(:,1),'stable');
vnew = v(iv,:);
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