how to modify a structure?

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UPT
UPT 2012-9-16
Hello. I initialize (instantiate) a structure like this:
YourStruct = struct(...
'Date', {cell(2208,1)}, ...
'Hour', {zeros(2208,1)}, ...
'DryBulb', {zeros(2208,1)}, ...
'DewPnt', {zeros(2208,1)}, ...
'SYSLoad', {zeros(2208,1)}, ...
'NumDate', {zeros(2208,1)});
'Date' has 92 days, and 'Hour' has 24 hours, from 1 to 24. How can I express 'Date' and 'Hour' in serial date numbers and how do I present these serial date numbers in 'NumDate'? Thank you.
  7 个评论
UPT
UPT 2012-9-16
编辑:Oleg Komarov 2012-9-16
sorry again for my mistakes Walter Roberson: here is my new post:
data = struct('Date', {cell(2208,1)}, 'Hour', {zeros(2208,1)}, 'DryBulb', {zeros(2208,1)}, 'DewPnt', {zeros(2208,1)}, 'SYSLoad', {zeros(2208,1)}, 'NumDate', {zeros(2208,1)});
'Date' has 92 days and 'Hour' has 24 hours,from 1 to 24.how can i express 'Date' and 'Hour' in serial date numbers and to present these serial date numbers in 'NumDate'?
Walter Roberson
Walter Roberson 2012-9-16
Blank line before and after the code. Indent the code.

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回答(1 个)

Walter Roberson
Walter Roberson 2012-9-16
NumDate = Data.Date + (Data.Hour - 1) / 24;
  5 个评论
UPT
UPT 2012-9-17
for each day i want to have 24 date serial numbers (a date serial number for each hour).could please you tell me how i can do that?...note:im a new user in matlab and i make some basic mistakes,so dont be upset if i dont understand all what you say..anyway,this is the fourth time you help me and im very grateful to you..:)
Walter Roberson
Walter Roberson 2012-9-17
Your Hour field is the same length as your Date field, which suggests you want exactly 1 hour conversion for each Date converted, rather than wanting to create 24 hour conversions for each Date converted.
data.NumDate = datenum(Data.Date) + (Data.Hour - 1) / 24;
except that you might need to add an additional parameter to datenum() in order to indicate the date format.

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