While loop in while loop; Shortening
24 次查看(过去 30 天)
显示 更早的评论
I want an overall while loop that is executed until a certain condition is true (let's say J=13).
The whole loop starts with J=5 and j=1 and inside the while loop j is raised +1 until j =J. Then the second while loop starts with J = J+1.
How can I shorten this code with one while loop ?
J=5;
j=1;
while (j<7)
if (j>J)
break
end
z=63*pi*(J-j);
j=j+1;
disp(z)
end
J=J+1;
j=1;
while (j<7)
if (j>J)
break
end
z=63*pi*(J-j);
j=j+1;
disp(z)
end
J=J+1;
j=1;
while (j<7)
if (j>J)
break
end
z=63*pi*(J-j);
j=j+1;
disp(z)
end
..... (and so on until J=13)
0 个评论
采纳的回答
Turlough Hughes
2019-10-7
编辑:Turlough Hughes
2019-10-7
You could try the following.
J=5;
while J<13
if J>=7
j=1:6;
else
j=1:J;
end
z=63*pi.*(J-j); %piecewise multiplication
disp(z)
J=J+1;
end
This satisfies the conditions of j less than or equal to J and j less than 7.
When j is not changing in size, i.e. after the first two iterations of the loop, you could in fact get a solution therein without any loops:
j=1:6;
J=[7:13]';
z=63*pi.*(J-j)
2 个评论
Turlough Hughes
2019-10-7
You just need to rearrange your order when initially specifying j and J. i.e. j is now a column vector while J is now a row vector.
j=[1:6]';
J=7:13;
z=63*pi.*(J-j)
更多回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息
产品
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!