Save elements of an array in a byte variable.
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Hi to every one!
I've got a problem with an easy programming excercise.
I've got a logical matrix composed by logical elements ( mat(32,5) ). I need for each row to save the first 8 elements af the array in 1 byte variable, elements from 9 to 16 in a second byte and so on..
So that the end I will have 4 byte variables for each row to sent to arduino.
How can I do that? thank you all.
2 个评论
David Hill
2019-10-7
I'm not sure what your matrix looks like. Is it a logical matrix 4x8? (what is mat(32,5)? Do you want the bytes in decimal form? What format do you want you output array?
I'm sorry for the lack of information.
My basic problem is that I can't create bytes from the elements of an array.
Let's say we have a logical array of 16 elements. I will then modify the solution for my specific case.
A=[0 0 1 0 0 0 0 0 0 0 0 0 1 1 0 0 ]
logA=logical(A);
How from this array can I create two uint8 in a way that:
var1=0b00100000;
var2=0b00001100;
采纳的回答
Johannes Fischer
2019-10-8
% random array of 8 rows with 4 bytes each
bin = logical(round(rand(8, 32)));
% how many bytes are there in total
NoBytes = size(bin, 2)/8*size(bin, 1);
% reshape the matrix into an array, where each row repsresents one byte
bArray = reshape(bin', [8, NoBytes])';
% now convert it into a cell array, where each cell contains a matrix of 8
% elements
bCell = num2cell(bArray, 2);
% now we take a detour over string represenation of the values to create a
% byte variable in each cell entry
bytes = cellfun(@(x) uint8(bin2dec(num2str(x))), bCell);
% reshape back into the original shape
bytes = reshape(bytes, [size(bin, 2)/8, size(bin, 1)])';
1 个评论
Eric Prandovsky
2023-11-3
编辑：Eric Prandovsky
2023-11-3
I've used typecast(X,type) before, but it doesn't accept logical data for some reason. This is a good workaround.
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