Why is this not outputting anything?

Question

Hunter Steele 2019-10-9

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/484296-why-is-this-not-outputting-anything

编辑： Adam Danz 2019-10-9

function output = MyMin(x)
MIN_VALUE=0;
[m, n]=size(x);
for i=1:length(x)
    if MIN_VALUE>x(i)
        MIN_VALUE=x(i);
        index=i;
        output = [MIN_VALUE, index];
    end
end

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Answer 1

meghannmarie 2019-10-9

0
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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/484296-why-is-this-not-outputting-anything#answer_395414

编辑：meghannmarie 2019-10-9

在 MATLAB Online 中打开

For this to work you need to set your intial MIN_VALUE to inf rather than 0. If its set to zero, it will only make output if you send it a negative number, otherwise it will never go into that if statement.

function output = MyMin(x)
MIN_VALUE=inf;
for i=1:length(x)
    if MIN_VALUE>x(i)
        MIN_VALUE=x(i);
        index=i;
        output = [MIN_VALUE, index];
    end
end
end

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Hunter Steele 2019-10-9

Thank you for making that clear!

Adam Danz 2019-10-9

编辑：Adam Danz 2019-10-9

在 MATLAB Online 中打开

I didn't see meghannmarie's answer, before posting mine (minutes apart). I just wanted to add that the min() function does what you're loop is doing and it's a lot more efficient.

[MIN_VALUE, index] = min(x);

The only difference is that the min() function splits the output into two while yours reutrns a 1x2 vector.

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