How do I go about plotting the following function?

Question

0 个投票

The function I want to plot is x[n] = \delta[n] - \delta[n-a] where a is just a number.

I tried following this tutorial, but I always ended up with out of memory errors.

I know about plotting the impulse function on it's own but this doesn't make any sense to me.

Any and all help is appreciated.

1 个评论
显示 -1更早的评论隐藏 -1更早的评论

John Doe 2019-10-9

Please share your code.

Answer 1

John Doe 2019-10-9

编辑：John Doe 2019-10-10

0 个投票

I've used random numbers.

a = 5
n = [1:1:50]';
delta = 10;
x(n,1) = delta - (delta*(n-a))
plot(x,n)

Alternatively, you could leave n as it is without transposing and plot per the below:

a = 5
n = 1:1:50;
delta = 10;
x(n,1) = delta - (delta*(n-a))
plot(x(:,1),n(1,:))

It doesn't make much odds.

SF 2019-10-9

How did you plot this then? I'm getting that x and n aren't the same size.

John Doe 2019-10-10

编辑：John Doe 2019-10-10

This was your size error. I've updated the answer to transpose n in to be the same as x.

 size(x)
ans =
    50     1
 
 size(n)
ans =
     1    50

Please accept answer :)