Comparing elements of a vector.

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Madhurima Reddy
Madhurima Reddy 2019-10-10
评论： Madhurima Reddy 2019-10-10
I have two vectors named R and T, where elements in R keep on increasing and finally reaches a steady state value.
Let's say T = [1;2;3;4;5;6;7;8;9;10;11;12;13;14;15;16;17;18;19;20;21] and R = [1;2;3;4;5;6;7;8;9;10;10;10;11;12;12;12;12;12;13;13;13].
I intend to get g(:,1) = [1;2;3;4;5;6;7;8;9;10;13;14;19] and g(:,2) = [1;2;3;4;5;6;7;8;9;10;11;12;13]. But I am getting all the values in g. Could you please help me out with this.
Thanks and Regards.
L = length(R);
for h = 1:1:L-1
dffrad = R(h+1)-R(h);
dfftime= T(h+1)-T(h);
if (dffrad~=0 && dffrad>0)
g = [g; T(h+1) R(h+1)];
end
end
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Madhurima Reddy
Madhurima Reddy 2019-10-10
The values in my data(not that's given in the question) were getting rounded off to nearest decimal and that's why I thought the values were repeating. Thank you Shubham for your help.
Shubham Gupta
Shubham Gupta 2019-10-10
I am glad I could help. Also, you might wanna look at @the_cyclist 's answer for better performance.

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回答（1 个）

the cyclist
the cyclist 2019-10-10
[g(:,2), idx] = unique(R);
g(:,1) = T(idx);
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the cyclist
the cyclist 2019-10-10
You are correct.
But the original question explicitly stated that R is increasing, so I assumed that that was OK.
Madhurima Reddy
Madhurima Reddy 2019-10-10
My data does decrease after reaching a max value. However, Thank you to both of you for help.

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