How this is possible? "atan(x) function problem"

4 次查看(过去 30 天)
Hello Everyone!
I want to calculate the arctan function in MatLab.
But the result is a situation that I do not understand.
Normally, x = atan (1/0) is compleately NaN
Also, matlab says that x = arctan (1/0)
= 1.5708
How is that possible?
Sorry about this simple question but I could not find any information on the network.

采纳的回答

Hemant Verma
Hemant Verma 2019-10-11
Just recall the basics of trigonometry, for a right-angled triangle
,
where P denotes perpendicular, B denotes base and θ denotes angle between hypotenuse and base of triangle.
In your case, where you want to compute arctan(1/0), the length of base B of triangle becomes 0. As B tends to 0, the hypotenuse and perpendicular of triangle start becoming colinear, and θ tends to 90 degrees or (i.e 1.5708) radians.
That's why you get

更多回答(1 个)

Stephan
Stephan 2019-10-11
编辑:Stephan 2019-10-11
What is the problem?
a = 1/0
a =
Inf
atan(a)
ans =
1.5708
fplot(@(x)atan(x),[-100 100],'-b','LineWidth',2)
looks like the Wiki-Entry for me:

类别

Help CenterFile Exchange 中查找有关 Introduction to Installation and Licensing 的更多信息

标签

产品


版本

R2019b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by