How to shift a matrix
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Say I have a matrix that is 3x3:
1 2 3
4 5 6
7 8 9
I want to shift the top and bottom rows:
1 2 3
4 5 6
7 8 9
This would expand it into a 3x4 matrix yes but i mostly want to know how specifically to do this shifting. I was told the imwarp function could help but im not sure. I'm thinking I would have to define a matrix for the first one to shift to? Or something like that?
4 个评论
the cyclist
2019-10-11
Do you mean a numeric array, or a cell array?
If a numeric array, what do you want in the "empty" spaces (which cannot be empty in a numeric array). Zero? NaN?
Aldo Hernandez
2019-10-11
Adam
2019-10-11
They way you have drawn your shifting suggests more than a 3x4 output as your shifted numbers fall in the gaps between the row below/above, which would require a larger matrix to include. Or are the 1, 5 and 7 supposed to all line up in the 2nd column?
Aldo Hernandez
2019-10-11
采纳的回答
prasanth s
2019-10-11
loop version:
M=[ 1,2,3;
4,5,6;
7,8,9; ];
C=nan(3,4);
for i=1:size(M,1)
if mod(i,2)==1
C(i,2:end)=M(i,:);
else
C(i,1:end-1)=M(i,:);
end
end
vector slicing version:
M=[ 1,2,3;
4,5,6;
7,8,9; ];
L=mod([1:3]',2)>0;%logical 1 and 0 vector
A=M(L,:);
B=M(not(L),:);
C=nan(3,4);
C(L,2:4)=A;
C(not(L),1:3)=B;
M is input array
C is output array
empty elements is in 'NaN' type. you can get nan value index using 'isnan' function
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