Remove strings from an array based on string length
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Hello. I'm trying to remove strings from a string array based on string length. I want to remove strings with lesser than 2 alphabets. I tried the following code but I'm getting an error
clc; clear;
s = {'a';'b';'cat';'apple'};
s1 = string(s);
String_length = strlength(s1);
Min_length = 2;
Modified_string = [s1 String_length];
indices = find(Modified_string(:,2) < Min_length);
Modified_string(indices,:) = [];
Error using <
Comparison between string and double is not supported.
Error in Dummy (line 8)
indices = find(Modified_string(:,2) < Min_length);
1 个评论
This approach is very complex, with one implicit conversion from numeric to string, which then requires an explicit conversion from string to numeric. Pointless type conversions should be avoided, as they just slow code down without any benefit.
Here is a much simpler and more efficient solution using basic MATLAB indexing:
out = s1(strlength(s1)>=2))
采纳的回答
Thiago Henrique Gomes Lobato
2019-10-13
For you to do the comparison you must first convert the string to a numeric. The following code should solve your problem:
clc; clear;
s = {'a';'b';'cat';'apple'};
s1 = string(s);
String_length = strlength(s1);
Min_length = 2;
Modified_string = [s1 String_length];
indices = find( str2double(Modified_string(:,2)) < Min_length);
Modified_string(indices,:) = []
Modified_string =
2×2 string array
"cat" "3"
"apple" "5"
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2019-10-13
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